What's an elegant way to test for list index existing?
jladasky at itu.edu
jladasky at itu.edu
Fri Sep 28 17:35:38 EDT 2018
On Friday, September 28, 2018 at 11:03:17 AM UTC-7, Chris Green wrote:
> I have a list created by:-
>
> fld = shlex.split(ln)
>
> It may contain 3, 4 or 5 entries according to data read into ln.
> What's the neatest way of setting the fourth and fifth entries to an
> empty string if they don't (yet) exist? Using 'if len(fld) < 4:' feels
> clumsy somehow.
How about this?
from itertools import chain, repeat
temp = shlex.split(ln)
fld = list(chain(temp, repeat("", 5-len(temp))))
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