Function to determine list max without itertools

Chris Angelico rosuav at
Thu Apr 18 04:17:09 EDT 2019

On Thu, Apr 18, 2019 at 5:41 PM Sayth Renshaw <flebber.crue at> wrote:
> Thank you for the advice everyone.
> >
> > The first thing to try is find every place where you update myMax, and
> This was actually where I was going wrong. I was setting max but then overwriting it with item. Then kept checking item only to return myMax.
> I went looking for other solutions as I thought I must be well off the path in the shrubs but I was actually close.
> This is how I ended up. There may be better solutions but this works.
> def maximum(listarg):
>     items = list(listarg)
>     myMax = items[0]
>     for item in items:
>         for i in items[items.index(item)+1:len(items)]:
>             if myMax < i:
>                 myMax = i
>             else:
>                 pass
>     return myMax
> if __name__ == "__main__":
>     print(maximum([4,3,6,2,1,4]))

This is where I would strongly recommend printing lots of stuff out,
to explore what the algorithm is doing at each point. See if you can
figure out when myMax is being updated.

(Also: items.index(item) will potentially give the wrong result if you
have duplicates.)


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