How to catch a usefull error message ?
MRAB
python at mrabarnett.plus.com
Tue Apr 23 13:27:53 EDT 2019
On 2019-04-23 10:56, Vincent Vande Vyvre wrote:
> Hi,
>
> In a CPython lib I have an _init() method wich take one argument, a file
> name.
>
> char *fname;
>
> if (!PyArg_ParseTuple(args, "s", &fname))
> return NULL;
>
> So, if I instanciate my object with a bad argument I've a good error
> message:
>
> tif = ImgProc(123)
> TypeError: argument 1 must be str, not int
> (followed by the traceback)
>
> But if I do:
> try:
> tif = ImgProc(123)
> except Exception as why:
> print("Error:", why)
>
> I get just:
>
> Error: <class '_liboqapy.ImgProc'> returned a result with an error set
>
> Without traceback. That's not very usefull.
>
> I prefer to keep the instanciation of this object into a try-except bloc
> but how to read the error message ?
>
Have a look ta the 'traceback' module.
Example:
import traceback
try:
1/0
except Exception as ex:
print('Error:', ex)
traceback.print_exc()
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