pysftp / paramiko problem
Robin Becker
robin at reportlab.com
Tue Jun 11 10:23:52 EDT 2019
I am trying to convert older code that uses ftplib as the endpoint has switched to sftp only.
I am using the pysftp wrapper around paramiko.
The following script fails
def main():
import pysftp
with pysftp.Connection('ftp.remote.com', username='me', password='xxxxxx') as sftp:
print('top level')
print(sftp.listdir())
print(sftp.normalize(u'XXXX'))
print('direct list of XXXX')
print(sftp.listdir(u'XXXX'))
with sftp.cd(u'XXXX'):
print(sftp.listdir())
if __name__ == '__main__':
main()
when run the program prints [u'XXXX'] and then fails at the normalize command.
> $ python tsftp.py
> top level
> [u'XXXX']
> Traceback (most recent call last):
> File "tsftp.py", line 13, in <module>
> main()
> File "tsftp.py", line 6, in main
> print(sftp.normalize(u'XXXX'))
> File "/home/rptlab/devel/env/lib/python2.7/site-packages/pysftp/__init__.py", line 640, in normalize
> return self._sftp.normalize(remotepath)
> File "/home/rptlab/devel/env/lib/python2.7/site-packages/paramiko/sftp_client.py", line 632, in normalize
> t, msg = self._request(CMD_REALPATH, path)
> File "/home/rptlab/devel/env/lib/python2.7/site-packages/paramiko/sftp_client.py", line 813, in _request
> return self._read_response(num)
> File "/home/rptlab/devel/env/lib/python2.7/site-packages/paramiko/sftp_client.py", line 865, in _read_response
> self._convert_status(msg)
> File "/home/rptlab/devel/env/lib/python2.7/site-packages/paramiko/sftp_client.py", line 894, in _convert_status
> raise IOError(errno.ENOENT, text)
> IOError: [Errno 2] No such file.
I tried other commands, but it seems any attempt to cd to the XXXX directory fails.
Using sftp in the shell directly I needed to add HostKeyAlgorithms=+ssh-dss for this host.
Any pointers to what the problem could be?
--
Robin Becker
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