How do I give a decorator acces to the class of a decorated function
Antoon Pardon
antoon.pardon at vub.be
Thu Sep 5 04:00:19 EDT 2019
On 4/09/19 17:46, Peter Otten wrote:
> Antoon Pardon wrote:
>
>> What I am trying to do is the following.
>>
>> class MyClass (...) :
>> @register
>> def MyFunction(...)
>> ...
>>
>> What I would want is for the register decorator to somehow create/mutate
>> class variable(s) of MyClass.
>>
>> Is that possible or do I have to rethink my approach?
> If you are willing to delegate the actual work to the metaclass call:
>
> def register(f):
> f.registered = True
> return f
>
> def registered(name, bases, namespace):
> namespace["my_cool_functions"] = [
> n for n, v in namespace.items()
> if getattr(v, "registered", False)
> ]
> return type(name, bases, namespace)
>
> class MyClass(metaclass=registered) :
> @register
> def foo(self):
> pass
> @register
> def bar(self):
> pass
> def other(self):
> pass
>
> print(MyClass.my_cool_functions)
Thanks for this idea. I think I can make this work for me.
--
Antoon.
More information about the Python-list
mailing list