How do I do this in Python 3 (string.join())?

[Chris Green]

I have the following line in Python 2:-

    msgstr = string.join(popmsg[1], "\n")      # popmsg[1] is a list containing the lines of the message

... so I changed it to:-

    s = "\n"
    msgstr = s.join(popmsg[1])      # popmsg[1] is a list containing the lines of the message

However this still doesn't work because popmsg[1] isn't a list of
strings, I get the error:-

    TypeError: sequence item 0: expected str instance, bytes found

So how do I do this?  I can see clumsy ways by a loop working through
the list in popmsg[1] but surely there must be a way that's as neat
and elegant as the Python 2 way was?

-- 
Chris Green
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