dict.get(key, default) evaluates default even if key exists
Chris Angelico
rosuav at gmail.com
Tue Dec 15 13:57:06 EST 2020
On Wed, Dec 16, 2020 at 4:58 AM Mark Polesky via Python-list
<python-list at python.org> wrote:
>
> Hi.
>
> # Running this script....
>
> D = {'a':1}
> def get_default():
> print('Nobody expects this')
> return 0
> print(D.get('a', get_default()))
>
> # ...generates this output:
>
> Nobody expects this
> 1
>
> ###
>
> Since I'm brand new to this community, I thought I'd ask here first... Is this worthy of a bug report? This behavior is definitely unexpected to me, and I accidentally coded an endless loop in a mutual recursion situation because of it. Calling dict.get.__doc__ only gives this short sentence: Return the value for key if key is in the dictionary, else default. Nothing in that docstring suggests that the default value is evaluated even if the key exists, and I can't think of any good reason to do so.
>
> Am I missing something?
>
Seems what you want is the __missing__ method. Look into it - I think
it will do what you're expecting here.
ChrisA
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