dict.get(key, default) evaluates default even if key exists
jak
nospam at please.ty
Thu Dec 17 07:10:17 EST 2020
Il 17/12/2020 12:40, Peter J. Holzer ha scritto:
> On 2020-12-17 12:16:29 +0100, jak wrote:
>> print(_ if d.get('a', None) is not None else get_default())
>
> That doesn't work:
>
>>>> print(_ if d.get('a', None) is not None else get_default())
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> NameError: name '_' is not defined
>
> But this works:
>
>>>> print(_ if (_ := d.get('a', None)) is not None else get_default())
> 1
>
> (I would prefer ChrisA's solution, though.)
>
> hp
>
this one?
""""
D['a'] if 'a' in D else get_default()
ChrisA
""""
This solution search two times same key.
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