execution timing of the method QWidget.show()
Barry
barry at barrys-emacs.org
Wed Jul 8 18:26:39 EDT 2020
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Barry
> On 8 Jul 2020, at 21:17, artis.paintre at gmail.com wrote:
>
> I might be wrong but since I have not found anygroup newsgroup dedicated to PyQt5.
>
> My small program is expected to show a window GUI for 4 seconds before changing it, so I naively coded:
>
> "...
> ...
> # codes to set up the GUI
> ...
> F0.show() # F0 being a QMainWindow object
> time.sleep(4)
> ...
> # codes to change the GUI set up
> ...
> F0.update()
>
> "
>
> What happens: The a blank window is displayed, freezes for 4 seconds then second set up is displayed, the original set up is not displayed.
>
> Why is not the original set up displayed?
>
> Obviously, if I remove the codes for the second set up, and the "time.sleep(4)" instruction, the original set up is displayed immediatly after I launch the execution.
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