primitive password cracker
Bischoop
Bischoop at vimart.net
Thu Jan 7 11:45:08 EST 2021
On 2021-01-07, David Raymond <David.Raymond at tomtom.com> wrote:
> I think you might want to check out itertools.product()
> https://docs.python.org/3.9/library/itertools.html#itertools.product
Thanks David for contribution I find it very convenient but not knowing
how to solve solution without itertools for:
for a i xxxx:
for b in xxxx:
for c in xxxx:
for d in xxxx:
doesn't give me a peace.
--
Thanks
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