count consecutive elements
Peter Otten
__peter__ at web.de
Tue Jan 19 03:51:16 EST 2021
On 19/01/2021 04:45, Bischoop wrote:
> I sat to it again and solved it.
Congratulations!
> lil = tuple(set(s)) # list of characters in s
>
> li=[0,0,0,0,0,0] # list for counted repeats
I see a minor problem here. What happens if s contains more than len(li)
characters?
> import timeit
Since you seem interested in performance: imagine that the input is a
very long string. Let's call the length N.
How often do you iterate over its characters?
How often does Tim's solution?
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