Unexpected behaviour of math.floor, round and int functions (rounding)

MRAB python at mrabarnett.plus.com
Thu Nov 18 21:51:04 EST 2021


On 2021-11-19 02:40, 2QdxY4RzWzUUiLuE at potatochowder.com wrote:
> On 2021-11-18 at 23:16:32 -0300,
> René Silva Valdés <rene.silva.valdes at gmail.com> wrote:
> 
>> Hello, I would like to report the following issue:
>> 
>> Working with floats i noticed that:
>> 
>> int(23.99999999999999/12) returns 1, and
>> int(23.999999999999999/12) returns 2
>> 
>> This implies that int() function is rounding ...
> 
> It's not int() that's doing the rounding; that second numerator is being
> rounded before being divided by 12:
> 
>      Python 3.9.7 (default, Oct 10 2021, 15:13:22)
>      [GCC 11.1.0] on linux
>      Type "help", "copyright", "credits" or "license" for more information.
>      >>> 23.999999999999999
>      24.0
>      >>> (23.999999999999999).hex()
>      '0x1.8000000000000p+4'
> 
I think this is a bit clearer because it shows that it's not just being 
rounded for display:

Python 3.10.0 (tags/v3.10.0:b494f59, Oct  4 2021, 19:00:18) [MSC v.1929 
64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
 >>> 23.99999999999999 == 24
False
 >>> 23.999999999999999 == 24
True


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