getting source code line of error?
Ulli Horlacher
framstag at rus.uni-stuttgart.de
Fri Nov 19 07:09:26 EST 2021
I am trying to get the source code line of the last error.
I know traceback.format_exc() but this contains much more information, e.g.:
Traceback (most recent call last):
File "./error.py", line 18, in main
x=1/0
ZeroDivisionError: division by zero
I could extract the source code line with re.search(), but is there an
easier way?
I have:
exc_type,exc_str,exc_tb = sys.exc_info()
fname = exc_tb.tb_frame.f_code.co_filename
line = exc_tb.tb_lineno
print('%s in %s line %d' % (exc_str,fname,line))
But I also want to output the line itself, not only its number.
--
Ullrich Horlacher Server und Virtualisierung
Rechenzentrum TIK
Universitaet Stuttgart E-Mail: horlacher at tik.uni-stuttgart.de
Allmandring 30a Tel: ++49-711-68565868
70569 Stuttgart (Germany) WWW: http://www.tik.uni-stuttgart.de/
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