matrix row comparison and fetch data with numpy

variety jones varietyjones10 at
Tue Oct 26 07:20:59 EDT 2021

I have 2 matrix with , M and M' , The M' matrix is the result of calculation "order preserving" of the matrix M  so i will explain more by examples , so here is the matrix M : 

    M= np.array([

so lets take the row L1 from the matrix M so the smallest integer is  - 1 so we take the position of -1 from the matrix M which is in the column C3 and write 1 in L1 of the matrix M', and here we go for the other numbers we compare them and take the right order , in case of similarity we give them the same order , 
this part is looking fine i write a program who take a matrix and calculate the order preserving of it and show the results in the second matrix , here is my code :

so the second step is , We will take the columns similar to X% from the matrix M'

In this case there are two conditions : X% = 100% similar
The number of minimum similar columns  : 𝑁𝑏𝑟𝑒 𝑐𝑜𝑙 𝑚𝑖𝑛=2

so from the matrix M' we will compare row by row : L1 to L2 , L2 to L 3 until we find similar rows and here is the results : 
Seed1= {L1 l2 c2 c4 c6}
Seed2= {L1 l3 c1 c3 c5}
Seed3={L3 l6 c2 c4 c5}
Seed4={L4l6 c3 c6}
Seed5= {L7 l8 c3 c5 c6}
In order to build a bi-group , We must combine the seeds with each other: we will unite the rows of the seed and the intersection of the columns of the seed By respecting: 𝑁𝑏𝑟𝑒 𝑐𝑜𝑙 𝑚𝑖𝑛 = 2 
the final results :
Bi-groupe 1={L1 l2 l3 l6 c2 c4}
Bi-groupe2={L1 l3 l7 l8 c3 c5}
Bi-groupe  3={L4 l6 l7 l8 c3 c6}

i just want a function or  away to figured out the seeds by rows comparison  and show the bi-groupe results 

Many Thanks

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