Superclass static method name from subclass

[Ian Pilcher]

On 11/11/22 11:29, Dieter Maurer wrote:
> Ian Pilcher wrote at 2022-11-11 10:21 -0600:
>>
>>    class SuperClass(object):
>>        @staticmethod
>>        def foo():
>>            pass
>>
>>    class SubClass(SuperClass):
>>        bar = SuperClass.foo
>>              ^^^^^^^^^^
>>
>> Is there a way to do this without specifically naming 'SuperClass'?
> 
> Unless you overrode it, you can use `self.foo` or `SubClass.foo`;
> if you overrode it (and you are using either Python 3 or
> Python 2 and a so called "new style class"), you can use `super`.
> When you use `super` outside a method definition, you must
> call it with parameters.

SubClass.foo doesn't work, because 'SubClass' doesn't actually exist
until the class is defined.

 >>> class SubClass(SuperClass):
...   bar = SubClass.foo
...
Traceback (most recent call last):
   File "<stdin>", line 1, in <module>
   File "<stdin>", line 2, in SubClass
NameError: name 'SubClass' is not defined. Did you mean: 'SuperClass'?

Similarly, self.foo doesn't work, because self isn't defined:

 >>> class SubClass(SuperClass):
...   bar = self.foo
...
Traceback (most recent call last):
   File "<stdin>", line 1, in <module>
   File "<stdin>", line 2, in SubClass
NameError: name 'self' is not defined

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