How to 'ignore' an error in Python?
Chris Green
cl at isbd.net
Fri Apr 28 11:55:41 EDT 2023
I'm sure I'm missing something obvious here but I can't see an elegant
way to do this. I want to create a directory, but if it exists it's
not an error and the code should just continue.
So, I have:-
for dirname in listofdirs:
try:
os.mkdir(dirname)
except FileExistsError:
# so what can I do here that says 'carry on regardless'
except:
# handle any other error, which is really an error
# I want code here to execute whether or not dirname exists
Do I really have to use a finally: block? It feels rather clumsy.
I suppose I could test if the directory exists before the os.mkdir()
but again that feels a bit clumsy somehow.
I suppose also I could use os.mkdirs() with exist_ok=True but again
that feels vaguely wrong somehow.
--
Chris Green
ยท
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