How to 'ignore' an error in Python?
Mats Wichmann
mats at wichmann.us
Fri Apr 28 12:39:36 EDT 2023
On 4/28/23 09:55, Chris Green wrote:
> I'm sure I'm missing something obvious here but I can't see an elegant
> way to do this. I want to create a directory, but if it exists it's
> not an error and the code should just continue.
>
> So, I have:-
>
> for dirname in listofdirs:
> try:
> os.mkdir(dirname)
> except FileExistsError:
> # so what can I do here that says 'carry on regardless'
> except:
> # handle any other error, which is really an error
>
> # I want code here to execute whether or not dirname exists
>
>
> Do I really have to use a finally: block? It feels rather clumsy.
For this specific case, you can use os.makedirs:
os.makedirs(dirname, exist_ok=True)
The mkdir in pathlib also takes the exist_ok flag
As to the way you asked the question, you can use "pass" or the ellipses
for the "# so what can I do here"
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