in Python? -- Chunk -- (ChunkC '(a a b b b)), ==> ((a 2) (b 3))

Rob Cliffe rob.cliffe at btinternet.com
Mon Jun 10 09:29:08 EDT 2024


import itertools

def chunk1(seq):
     return [ ch * len(list(grp)) for (ch, grp) in itertools.groupby(s) ]

def chunk2(seq):
     return [ (ch, len(list(grp))) for (ch, grp) in itertools.groupby(s) ]

s='aaabbccccaa'
print(chunk1(s))
print(chunk2(s))
###################################
Program output:
['aaa', 'bb', 'cccc', 'aa']
[('a', 3), ('b', 2), ('c', 4), ('a', 2)]

Rob Cliffe

On 09/06/2024 22:20, HenHanna via Python-list wrote:
>
> Chunk, ChunkC -- nice simple way(s) to write these in Python?
>
>
> (Chunk  '(a a   b    a a a   b b))
>     ==> ((a a) (b)  (a a a) (b b))
>
>
> (Chunk  '(a a a a   b   c c   a a   d   e e e e))
>     ==> ((a a a a) (b) (c c) (a a) (d) (e e e e))
>
>
> (Chunk  '(2 2   foo   bar bar   j j j   k   baz baz))
>     ==> ((2 2) (foo) (bar bar) (j j j) (k) (baz baz))
>
> _________________
>
> (ChunkC  '(a a   b b b))
>      ==> ((a 2)  (b 3))
>
> (ChunkC  '(a a   b      a a a   b b))
>      ==> ((a 2)  (b 1)  (a 3)   (b 2))



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