in Python? -- Chunk -- (ChunkC '(a a b b b)), ==> ((a 2) (b 3))

HenHanna HenHanna at devnull.tb
Tue Jun 11 18:07:34 EDT 2024


On 6/10/2024 6:29 AM, Rob Cliffe wrote:
> import itertools
> 
> def chunk1(seq):
>      return [ ch * len(list(grp)) for (ch, grp) in itertools.groupby(s) ]
> 
> def chunk2(seq):
>      return [ (ch, len(list(grp))) for (ch, grp) in itertools.groupby(s) ]
> 
> s='aaabbccccaa'
> print(chunk1(s))
> print(chunk2(s))
> ###################################
> Program output:
> ['aaa', 'bb', 'cccc', 'aa']
> [('a', 3), ('b', 2), ('c', 4), ('a', 2)]
> 
> Rob Cliffe
> 


thank you...   OMG... For 10 minutes... i was SO mystified by
the question...
                 How can this code work??? ,  when it's
                   > def chunk1(seq):
                      and it's  [s]   within the def-body ?

it seemed as if the Compiler was doing a DWIM (Do what i mean)  trick.



> On 09/06/2024 22:20, HenHanna via Python-list wrote:
>>
>> Chunk, ChunkC -- nice simple way(s) to write these in Python?
>>
>>
>> (Chunk  '(a a   b    a a a   b b))
>>     ==> ((a a) (b)  (a a a) (b b))
>>
>>
>> (Chunk  '(a a a a   b   c c   a a   d   e e e e))
>>     ==> ((a a a a) (b) (c c) (a a) (d) (e e e e))
>>
>>
>> (Chunk  '(2 2   foo   bar bar   j j j   k   baz baz))
>>     ==> ((2 2) (foo) (bar bar) (j j j) (k) (baz baz))
>>
>> _________________
>>
>> (ChunkC  '(a a   b b b))
>>      ==> ((a 2)  (b 3))
>>
>> (ChunkC  '(a a   b      a a a   b b))
>>      ==> ((a 2)  (b 1)  (a 3)   (b 2))
> 



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