Flubbed it in the second interation through the string: range error... HOW?
MRAB
python at mrabarnett.plus.com
Wed May 29 07:38:17 EDT 2024
On 2024-05-29 05:33, Kevin M. Wilson via Python-list wrote:
> The following is my effort to understand how to process a string, letter, by letter:
> def myfunc(name): index = 0 howmax = len(name) # while (index <= howmax): while (index < howmax): if (index % 2 == 0): print('letter to upper = {}, index {}!'.format(name[index], index)) name = name[index].upper() print('if block {} and index {}'.format(name[index], index)) elif (index % 2 > 0): print(index) print('Start: elseif block, index is {}, letter is {}'.format(index, name)) # print('letter to lower = {}'.format(name[index])) # print('Already lowercase do noting: name = {}'.format(name[index])) index += 1 # index = name.upper()
> return name
> myfunc('capitalism')
> Error message: Not making sense, index is 1, letter s/b 'a'letter to upper = c, index 0!
> if block C and index 0
> 1
> Start: elseif block, index is 1, letter is C
> ---------------------------------------------------------------------------
> IndexError Traceback (most recent call last)
> Cell In[27], line 21
> 17 # index = name.upper()
> 19 return name
> ---> 21 myfunc('capitalism')
>
> Cell In[27], line 8, in myfunc(name)
> 6 while (index < howmax):
> 7 if (index % 2 == 0):
> ----> 8 print('letter to upper = {}, index {}!'.format(name[index], index))
> 9 name = name[index].upper()
> 10 print('if block {} and index {}'.format(name[index], index))
>
> IndexError: string index out of range***************************************************
> So, I'm doing something... Stupid!!
> ***************************************************
> "When you pass through the waters, I will be with you: and when you pass through the rivers, they will not sweep over you. When you walk through the fire, you will not be burned: the flames will not set you ablaze."
> Isaiah 43:2
I think the code is this:
def myfunc(name):
index = 0
howmax = len(name)
# while (index <= howmax):
while (index < howmax):
if (index % 2 == 0):
print('letter to upper = {}, index {}!'.format(name[index],
index))
name = name[index].upper()
print('if block {} and index {}'.format(name[index], index))
elif (index % 2 > 0):
print(index)
print('Start: elseif block, index is {}, letter is
{}'.format(index, name))
# print('letter to lower = {}'.format(name[index]))
# print('Already lowercase do noting: name =
{}'.format(name[index]))
index += 1
# index = name.upper()
return name
myfunc('capitalism')
What is:
name = name[index].upper()
meant to be doing?
What it's _actually_ doing is getting the character at a given index,
converting it to uppercase, and then assigning it to `name`, so `name`
is now 1 character long.
It doesn't this when 'index' is 0, so after the first iteration, `name`
is a single-character string.
On the second iteration it raises IndexError because the string is only
1 character long and you're asking for `name[1]`.
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