[python-uk] Here's a little test

[python-uk@python.org]

Thanks Chris.

I've tried fiddling with this but see my reply to Simon.

Cheers.

Dale Strickland-Clark
Riverhall Systems Ltd. Custom database and Web applications.
http://www.riverhall.co.uk
Offices: London: 0870 321 0034 Wokingham: 0870 321 2378
Mobile 0701 071 DALE (3253)

 -----Original Message-----
From: 	Chris Miles [mailto:chris@psychofx.com] 
Sent:	Wed, 2002 August 28 15:42
To:	python-uk@python.org
Subject:	Re: [python-uk] Here's a little test

One of my favorite things about Python: ask the object itself!

>>> import os
>>> print os.execl.__doc__
execl(file, *args)

    Execute the executable file with argument list args, replacing the
    current process. 


So as *args says, after the file arg you can pass as many args as you
like.

A simple demo on Linux (don't have a win32 handy):

>>> os.execl('/bin/ls', '-a', '-l')
total 16
-r--------    1 root     users        3746 Aug 19 15:56 monitoring
drwxr-sr-x    2 root     users        4096 Aug 28 11:19 RCS
-r--------    1 root     users        2835 Aug 27 15:09 skinner
-r--r--r--    1 root     users        3217 Aug 28 11:19 WEBSERVER

Although strangely the first argument is being ignored.  A better
example:

>>> os.execl('/bin/echo', '111', '222', '333')
222 333

Is this a bug, or something I'm missing?

Ok, I just worked it out, in typical Unix exec fashion, the first argument
is actually the process name.  A final example shows this:

>>> os.execl('/bin/sleep', 'sleeeepy', '99')

(and in another shell:)

$ ps -ef |grep slee
cmiles   25260 22756  0 15:39 pts/4    00:00:00 sleeeepy 99

Not sure if win32 follows this behaviour as closely.

Hope that helps somebody anyway!

CM


On Wed, Aug 28, 2002 at 03:27:36PM +0100, dale@riverhall.co.uk wrote:
> I've posted this on clp but not had a response. I thought I'd test you
guys
> :o)
> 
> 
> I have a little program I've converted from Javascript which I use
> frequently. It doesn't work in Python because the last line keeps
> throwing the error:
> 
> Traceback (most recent call last):
>   File "I:\batch\ie.py", line 22, in ?
>     os.execl(iepath, args)
>   File "C:\Python22\Lib\os.py", line 266, in execl
>     execv(file, args)
> TypeError: execv() arg 2 must contain only strings
> 
> I have tried a variety of formats for the os.execl function,
> including:
> 
> os.execl(iepath, (args, ))
> os.execl(iepath, [args])
> os.execl(iepath, args)
> 
> but it always complains about arg 2 in this way.
> 
> What is execl on about?
> 
> Any help appreciated.

-- 
Chris Miles
chris@psychofx.com
http://www.psychofx.com/chris/

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