[python-uk] how to kill the server in program
Yang, W (Wanjuan)
w.yang at dl.ac.uk
Wed Feb 15 10:42:02 CET 2006
I am building a server program. I have seen some examples like the following:
# We'll pickle a list of numbers, yet again:
someList = [ 1, 2, 7, 9, 0 ]
pickledList = pickle.dumps ( someList )
# A revised version of our thread class:
class ClientThread ( threading.Thread ):
# Note that we do not override Thread's __init__ method.
# The Queue module makes this not necessary.
def run ( self ):
# Have our thread serve "forever":
# Get a client out of the queue
client = clientPool.get()
# Check if we actually have an actual client in the client variable:
if client != None:
print 'Received connection:', client [ 1 ] [ 0 ]
client [ 0 ].send ( pickledList )
for x in xrange ( 10 ):
print client [ 0 ].recv ( 1024 )
client [ 0 ].close()
print 'Closed connection:', client [ 1 ] [ 0 ]
# Create our Queue:
clientPool = Queue.Queue ( 0 )
# Start two threads:
for x in xrange ( 2 ):
# Set up the server:
server = socket.socket ( socket.AF_INET, socket.SOCK_STREAM )
server.bind ( ( '', 2727 ) )
server.listen ( 5 )
# Have the server serve "forever":
clientPool.put ( server.accept() )
Since the server main thread and child thread will run forever, my question is how can I exit the server nicely in the program when it is required (e.g no clients coming for a while) rather than using 'Ctrl-c' or kill the process.
another question is: Is that when the main thread is killed, then the child thread will stop as well? In this case, before killing the main thread, we have to make sure the child thread already finish its job. But how the main thread know whether the child thread finish the job or not. in other words, how does the main thread communicate the child thread?
Anybody know? Thanks in advance!
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