[python-uk] C is it faster than numpy
SW
walker_s at hotmail.co.uk
Fri Feb 25 04:53:20 EST 2022
I think it uses fortran (or used to?) but yes, still close to the metal.
Thanks,
S
On 25/02/2022 10:41, Giorgio Zoppi wrote:
> Well,
> numpy is written in C :) Maybe your C is not the numpy equivalent?
> Best Regards,
> Giorgio
>
> Il giorno ven 25 feb 2022 alle ore 09:03 BELAHCENE Abdelkader
> <abdelkader.belahcene at enst.dz> ha scritto:
>
> Hi,
> a lot of people think that C (or C++) is faster than python, yes I
> agree, but I think that's not the case with numpy, I believe numpy
> is faster than C, at least in some cases.
> *Is there another explanation ?
> Or where can find a doc speaking about the subject?
> *Thanks a lot
> Regards
> Numpy implements vectorization for arrays, or I'm wrong. Anyway
> here is an example Let's look at the following case:
> Here is the result on my laptop i3:
>
> Labs$ *python3 tempsExe.py 50000*
> sum with Python: 1250025000 and NumPy 1250025000
> time used Python Sum: *37.28 sec *
> time used Numpy Sum: *1.85 sec*
>
> Labs$ *./tt 50000 *
> * CPU time :7.521730
> The value : 1250025000
> *--------------------------------------------
>
> This is the Python3 program :
>
> import timeit as it
> import numpy as np
> import sys
> try :
> n=eval(sys.argv[1])
> except:
> print ("needs integer as argument") ; exit()
>
> a=range(1,n+1)
> b=np.array(a)
> def func1(): return sum(a)
> def func2(): return np.sum(b)
>
> print(f"sum with Python: {func1()} and NumPy {func2()} ")
> tm1=it.timeit(stmt=func1, number=n)
> print(f"time used Python Sum: {round(tm1,2)} sec")
> tm2=it.timeit(stmt=func2, number=n)
> print(f"time used Numpy Sum: {round(tm2,2)} sec")
>
> and Here the C program:
> #include <time.h>
> #include <stdio.h>
> #include <stdlib.h>
> long func1(int n){
> long r=0;
> for (int i=1; i<= n;i++) r+= i;
> return r;
> }
> int main(int argc, char* argv[]){
> clock_t c0, c1;
> long v,count; int n;
> if ( argc < 2) {
> printf("Please give an argument");
> return -1;
> }
> n=atoi(argv[1]);
> c0 = clock();
> *for (int j=0;j < n;j++) v=func1(n);*
> c1 = clock();
> printf ("\tCPU time :%.2f sec", (float)(c1 -
> c0)/CLOCKS_PER_SEC);
> printf("\n\tThe value : %ld\n", v);
> }
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>
> --
> Life is a chess game - Anonymous.
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