[python-win32] cwd of program

[Andre Burgaud]

Hi Le Dahut,

I use the following code for prgrams built with py2exe:

<snip>
import sys
import os
print os.path.dirname(sys.executable)
</snip>

This may work in your situation as well.

Regards,

Andre
http://www.burgaud.com/


On 10/21/05, le dahut <le.dahut at laposte.net> wrote:
>
> In fact I build an SFX archive with winrar where I specify a program to
> launch once extraction has ended. The program is launched but don't find
> it's sub-directory.
> If I go to the extracted archive directory an dlbe-clic on "install.exe"
> all runs fine, but whit winrar's "Run after extraction" option it
> doesn't.
>
>
> Le vendredi 21 octobre 2005 à 14:42 +0100, Tim Golden a écrit :
> > [le dahut]
> >
> > > I try to get the program's directory, the one where the .exe (or .py)
> > is.
> >
> > >From within Python, sys.argv[0] usually gives you the running
> > program (not sure what it does with py2exe etc.). So something
> > like (untested):
> >
> > <code>
> > import os, sys
> >
> > print os.path.dirname (sys.argv[0])
> >
> > </code>
> >
> > > With os.getcwd() I get the directory from where the program is
> > launched
> > > not his directory. The program has to copy some files and thus I get
> > an
> > > error like "XXXXXX no such file or directory".
> >
> > Umm. It's not clear why you get "no such file / directory". Surely
> > os.getcwd returns *some* real directory. Or is it that you don't
> > have permissions to the directory?
> >
> > > (the DOS box closed to quickly to have the detailed
> > > error msg...) where XXXXXX is a sub-directory of
> > > the program's one.
> >
> > I'm assuming you're double-clicking on a Python icon to
> > run the program. You might try, instead, running it from
> > the command line:
> >
> > Start > Run > cmd.exe
> > (DOS box opens)
> > python x:\path\to\my\program.py
> >
> > This should let you see what's going on.
> >
> > TJG
> >
> >
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