[python-win32] wrong results in service running mode
mhammond at skippinet.com.au
Thu Apr 20 01:01:43 CEST 2006
> One piece of the program is to check a file exist or not as follows:
> szNormPath= os.path.normpath(strFileName)
> nRetCode = os.access(szNormPath, os.F_OK)
> # nRetCode = os.path.exists(szNormPath)
> When the file path is C:\shared\t.txt, no problem.
> When the path becomes L:\t.txt, then I got problems:
> nRetCode always is False(0), here L: is a mapped drive
> L: = C:\shared. So L:\t.txt and C:\shared\t.txt
> point to the same file.
This is almost an FAQ for services and has nothing to do with Python.
When running from a DOS box, the service is running as your user, so has all
your drive mappings etc. When running as a service it generally runs as a
different user, so does not. Worse, the LocalSystem account generally has
no network access.
The solution is generally just to use the complete UNC name '\\server\share'
in your Python program - this generally works fine (but still will generally
*not* work for the LocalSystem account - so you will also need to change the
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