[python-win32] EasyDialogs - how to set initial path
John Machin
sjmachin at lexicon.net
Mon Jul 3 11:20:00 CEST 2006
On 30/06/2005 5:43 PM, Radovan Grznarik wrote:
> Hi,
>
> I am using EasyDialogs (AskFileForOpen) and I am not able to set the
> initial open path. I found in Python help that it should be 3rd
> parameter,
I doubt it. The Python *documentation*, whose first two lines ("2.7
EasyDialogs -- Basic Macintosh dialogs", "Availability: Macintosh.) are
easily ignored, does contain this:
AskFileForOpen( [message] [, typeList] [, defaultLocation] [,
defaultOptionFlags] etc etc.
But you are running on Windows, and to get as far as you did, you must
have downloaded Jimmy Retzlaff's 3rd party not quite-compatible subset
EasyDialogs module.
Then if you use the Python *help*, you get:
C:\junk>python
Python 2.4.2 (#67, Sep 28 2005, 12:41:11) [MSC v.1310 32 bit (Intel)] on
win32
Type "help", "copyright", "credits" or "license" for more information.
|>> import EasyDialogs
|>> EasyDialogs.__file__
'c:\\python24\\lib\\site-packages\\EasyDialogs\\__init__.pyc'
>>> help(EasyDialogs.AskFileForOpen)
Help on function AskFileForOpen in module EasyDialogs:
AskFileForOpen(message=None, typeList=None, version=None,
defaultLocation=None,
dialogOptionFlags=None, location=None, clientName=None,
[snip]
then I tried this
>
> filename = EasyDialogs.AskFileForOpen("title","*.*","d:\\")
>
> but it does not work, and opens dialog in actual directory of running script.
If it's any consolation, you're not the first to get trapped like this :-)
>
> os.chdir("d:\\") before AskFileForOpen also does not work.
>
Here's a handy tip: when a function has keyword arguments, use the
keywords -- not only does it save you counting args, it helps document
your code.
Here's a (slightly edited) example from one of my scripts:
import EasyDialogs
infname = EasyDialogs.AskFileForOpen(
windowTitle='Fu or Bar file from XYZ',
typeList=[
('All files (*.*)', '*.*'),
],
defaultLocation=r'G:\XYZfiles\FuBar',
# message='... a message',
)
Cheers,
John
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