[python-win32] Pywin32 Windows Service not responding

[Steven Manross]

Something seems to be stripping your code at about 40-50 characters and it seems like we are missing the right half of your code.

Example:

_svc_description_ = 'This is a sample Python Wind

Steven
From: python-win32 <python-win32-bounces+steven=manross.net at python.org> On Behalf Of jeremy.farmer1206 via python-win32
Sent: Friday, March 24, 2023 1:26 PM
To: python-win32 at python.org
Subject: [python-win32] Pywin32 Windows Service not responding

Hi, I am looking for some assistance with utilizing pywin32 in order to create a Windows Service.

I've tried to create as bare-bones of an application as I could inheriting from win32serviceutil.ServiceFramework

import traceback
import win32serviceutil
import win32service
import win32event
import servicemanager
import socket
import time
import os
import sys

class MyService(win32serviceutil.ServiceFramework):
    _svc_name_ = 'MyPythonService'
    _svc_display_name_ = 'My Python Service'
    _svc_description_ = 'This is a sample Python Wind

    def __init__(self, args):
        win32serviceutil.ServiceFramework.__init__(se
        self.hWaitStop = win32event.CreateEvent(None,
        socket.setdefaulttimeout(60)
        self.is_alive = True
    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE
        win32event.SetEvent(self.hWaitStop)
        self.is_alive = False

    def SvcDoRun(self):
        self.ReportServiceStatus(win32service.SERVICE
        self.ReportServiceStatus(win32service.SERVICE
        # win32event.WaitForSingleObject(self.hWaitSt
        try:
            servicemanager.LogMsg(servicemanager.EVEN
PYS_SERVICE_STARTED, (self._svc_name_, ''))
            self.main()
        except Exception as ex:
            servicemanager.LogErrorMsg("Exception in
eback.format_exc()))
            raise

    def main(self):
        while self.is_alive:
            with open('test.txt', 'a') as f:
                f.write('Service loop...')
                time.sleep(2)

if __name__ == '__main__':
    if len(sys.argv) == 1:
        servicemanager.Initialize()
        servicemanager.PrepareToHostSingle(MyService)
        servicemanager.StartServiceCtrlDispatcher()
    else:
        win32serviceutil.HandleCommandLine(MyService)


I've installed it via opening an admin command prompt and running

python main.py install

It installs successfully but if I attempt to run it, I get

[cid:image001.png at 01D95F42.26DA6EF0]

Or

>python main.py<http://main.py> start
Starting service MyPythonService
Error starting service: The service did not respond to the start or control request in a timely fashion.

debugging seems to work, or at least does not give any errors

python main.py<http://main.py> debug
Debugging service MyPythonService - press Ctrl+C to stop.
Info 0x40001002 - The MyPythonService service has started.

I believe my pywin32 is fully up to date

python -m pip install --upgrade pywin32
Requirement already satisfied: pywin32 in c:\users\jerem\appdata\local\programs\python\python311\lib\site-packages (305)

Misc

python --version
Python 3.11.2

[cid:834fd2a at proton.me]

Any assistance is very much appreciated!
Sent with Proton Mail<https://proton.me/> secure email.
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