[python-win32] Pywin32 Windows Service not responding

[Mark Hammond]

The last pywin32 release was before 3.11 was officially released, so 
maybe try either 3.10 or pywin32-306

Mark

On 25/03/2023 7:25 am, jeremy.farmer1206 via python-win32 wrote:
> Hi, I am looking for some assistance with utilizing pywin32 in order to 
> create a Windows Service.
> 
> I've tried to create as bare-bones of an application as I could 
> inheriting from win32serviceutil.ServiceFramework
> 
> import traceback
> import win32serviceutil
> import win32service
> import win32event
> import servicemanager
> import socket
> import time
> import os
> import sys
> class MyService(win32serviceutil.ServiceFramework):
>      _svc_name_ = 'MyPythonService'
>      _svc_display_name_ = 'My Python Service'
>      _svc_description_ = 'This is a sample Python Wind
>      def __init__(self, args):
>          win32serviceutil.ServiceFramework.__init__(se
>          self.hWaitStop = win32event.CreateEvent(None,
>          socket.setdefaulttimeout(60)
>          self.is_alive = True
>      def SvcStop(self):
>          self.ReportServiceStatus(win32service.SERVICE
>          win32event.SetEvent(self.hWaitStop)
>          self.is_alive = False
>      def SvcDoRun(self):
>          self.ReportServiceStatus(win32service.SERVICE
>          self.ReportServiceStatus(win32service.SERVICE
>          # win32event.WaitForSingleObject(self.hWaitSt
>          try:
>              servicemanager.LogMsg(servicemanager.EVEN
> PYS_SERVICE_STARTED, (self._svc_name_, ''))
>              self.main()
>          except Exception as ex:
>              servicemanager.LogErrorMsg("Exception in
> eback.format_exc()))
>              raise
>      def main(self):
>          while self.is_alive:
>              with open('test.txt', 'a') as f:
>                  f.write('Service loop...')
>                  time.sleep(2)
> if __name__ == '__main__':
>      if len(sys.argv) == 1:
>          servicemanager.Initialize()
>          servicemanager.PrepareToHostSingle(MyService)
>          servicemanager.StartServiceCtrlDispatcher()
>      else:
>          win32serviceutil.HandleCommandLine(MyService)
> 
> 
> I've installed it via opening an admin command prompt and running
> 
> python main.py install
> 
> It installs successfully but if I attempt to run it, I get
> 
> image.png
> 
> Or
> 
>     >python main.py <http://main.py> start
>     Starting service MyPythonService
>     Error starting service: The service did not respond to the start or
>     control request in a timely fashion.
> 
> 
> debugging seems to work, or at least does not give any errors
> 
>     python main.py <http://main.py> debug
>     Debugging service MyPythonService - press Ctrl+C to stop.
>     Info 0x40001002 - The MyPythonService service has started.
> 
> 
> I believe my pywin32 is fully up to date
> 
>     python -m pip install --upgrade pywin32
>     Requirement already satisfied: pywin32 in
>     c:\users\jerem\appdata\local\programs\python\python311\lib\site-packages (305)
> 
> 
> Misc
> 
>     python --version
>     Python 3.11.2
> 
> 
> image.png
> 
> Any assistance is very much appreciated!
> Sent with Proton Mail <https://proton.me/> secure email.
> 
> _______________________________________________
> python-win32 mailing list
> python-win32 at python.org
> https://mail.python.org/mailman/listinfo/python-win32