[Pythonmac-SIG] repeat loop question

[Bob Savage]

on 12/7/00 9:06 AM, tom smith wrote:
> 
> n = 0
> the_list = ["a", "b", "c"]
> 
> for i in the_list:
> print n, i
> n=n+1
> 
> 
> ...is there a way of getting the "count" of i without having to hand
> increment n?
> 

Remember that in your example above i is not an index into the_list, it is
the actual item. You need to use something like this instead:

>>> theList = ["a", "b", "c"]
>>> for i in range(len(theList)):
...     print i, theList[i]
... 
0 a
1 b
2 c

Bob