[Pythonmac-SIG] Leopard PyObjc & Quartz
Uliano Guerrini
guerrini.uliano at gmail.com
Tue Nov 6 14:40:10 CET 2007
Hello,
If I run the Examples in /Developer/Examples/Python/PyObjc/Quartz/...
building them from terminal with py2app the work as expected.
If I create a new project in Xcode with the any template Cocoa Python
Application and add in any file a line with
import Quartz
then the applicatons stops working (it hangs jumping in the dock) and
I can read in the console
[Session started at 2007-11-06 14:35:27 +0100.]
_RegisterApplication(), FAILED TO establish the default connection to
the WindowServer, _CGSDefaultConnection() is NULL.
2007-11-06 14:35:28.430 poppo[864:10b] *** -[NSRecursiveLock unlock]:
lock (<NSRecursiveLock: 0x1f8a150> '(null)') unlocked when not locked
2007-11-06 14:35:28.431 poppo[864:10b] *** Break on _NSLockError() to
debug.
2007-11-06 14:35:28.433 poppo[864:10b] *** -[NSRecursiveLock unlock]:
lock (<NSRecursiveLock: 0x1f8a150> '(null)') unlocked when not locked
2007-11-06 14:35:28.434 poppo[864:10b] *** Break on _NSLockError() to
debug.
2007-11-06 14:35:28.439 poppo[864:10b] *** -[NSRecursiveLock unlock]:
lock (<NSRecursiveLock: 0x1f8a150> '(null)') unlocked when not locked
2007-11-06 14:35:28.439 poppo[864:10b] *** Break on _NSLockError() to
debug.
2007-11-06 14:35:28.443 poppo[864:10b]
NSInternalInconsistencyException - Error (1002) creating CGSWindow
2007-11-06 14:35:28.447 poppo[864:10b] *** -[NSRecursiveLock unlock]:
lock (<NSRecursiveLock: 0x1f8a150> '(null)') unlocked when not locked
2007-11-06 14:35:28.447 poppo[864:10b] *** Break on _NSLockError() to
debug.
2007-11-06 14:35:28.449 poppo[864:10b] *** -[NSRecursiveLock unlock]:
lock (<NSRecursiveLock: 0x1f8a150> '(null)') unlocked when not locked
2007-11-06 14:35:28.449 poppo[864:10b] *** Break on _NSLockError() to
debug.
2007-11-06 14:35:28.450 poppo[864:10b] *** -[NSRecursiveLock unlock]:
lock (<NSRecursiveLock: 0x1f8a150> '(null)') unlocked when not locked
2007-11-06 14:35:28.450 poppo[864:10b] *** Break on _NSLockError() to
debug.
2007-11-06 14:35:28.451 poppo[864:10b] *** -[NSRecursiveLock unlock]:
lock (<NSRecursiveLock: 0x1f8a150> '(null)') unlocked when not locked
2007-11-06 14:35:28.452 poppo[864:10b] *** Break on _NSLockError() to
debug.
How am I supposed to use Quartz with pyobjc? (if it is possible within
xcode)
Uliano
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