My porblem understanding Local Binary Pattern

ginger wend gingerw at walla.com
Sat Jul 13 05:04:37 EDT 2013


Does it work with also with scikit-image 0.8 or only with 0.9dev?

Im using 0.8 and got some error regrarding label2rgb.


On Friday, July 12, 2013 6:30:06 PM UTC+2, Tony S Yu wrote:
>
>
>
>
> On Fri, Jul 12, 2013 at 7:13 AM, ginger wend <gin... at walla.com<javascript:>
> > wrote:
>
>> Hi,
>>
>> I am trying to learn Local Binary Pattern with scikit-image and as I have 
>> only limited knowledge in numpy and image analysis I find it hard. As a 
>> result, I will appreciate a lot if you can provide me some answers as I am 
>> sure that they will help me to advance:
>>
>> - If I understand correctly the 
>> skimage.feature.local_binary_pattern(image, P, R, method=' uniform) will go 
>> pixel by pixel (starting from pixel location 1,2) and generate the binary 
>> number based on the P and R, am I right?. If so what happens if the R is 
>> “out of boundary”?
>> - How do you calculate the histogram and why are there are 18 bins in the 
>> example (
>> http://scikit-image.org/docs/dev/auto_examples/plot_local_binary_pattern.html
>> )?
>> - The output is (N, M) array and when I look at it is not clear to me 
>> what is the output and how do you generate a histogram from it, can someone 
>> you please clarify it.
>>
>> I know that these questions are be basic and while I was trying to look 
>> for answers I found the information more mathematical and less with applied 
>> approach. Therefore, any help, ideas or tips will help.
>>
>> Thanks for the patience,
>> G.
>>
>> Hi,
>
> LBP can be quite confusing at first, but the idea is pretty simple. I 
> recently added some more explanations to the example in the gallery (most 
> of the addition is code to plot things---you don't really need to 
> understand that part of the code):
>
>
> https://github.com/scikit-image/scikit-image/blob/master/doc/examples/plot_local_binary_pattern.py
>
> That example should clarify most of your questions. I don't really know 
> how the boundary is treated, so maybe someone else can clarify that point.
>
> Best,
> -Tony
>
>
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