My porblem understanding Local Binary Pattern

[Johannes Schönberger]

I think, label2rgb was added in 0.9dev and thus is not available in 0.8.

Johannes Schönberger

Am 13.07.2013 um 11:04 schrieb ginger wend <gingerw at walla.com>:

> Does it work with also with scikit-image 0.8 or only with 0.9dev?
> 
> Im using 0.8 and got some error regrarding label2rgb.
> 
> 
> On Friday, July 12, 2013 6:30:06 PM UTC+2, Tony S Yu wrote:
> 
> 
> 
> On Fri, Jul 12, 2013 at 7:13 AM, ginger wend <gin... at walla.com> wrote:
> Hi,
> 
> I am trying to learn Local Binary Pattern with scikit-image and as I have only limited knowledge in numpy and image analysis I find it hard. As a result, I will appreciate a lot if you can provide me some answers as I am sure that they will help me to advance:
> 
> - If I understand correctly the skimage.feature.local_binary_pattern(image, P, R, method=' uniform) will go pixel by pixel (starting from pixel location 1,2) and generate the binary number based on the P and R, am I right?. If so what happens if the R is “out of boundary”?
> - How do you calculate the histogram and why are there are 18 bins in the example (http://scikit-image.org/docs/dev/auto_examples/plot_local_binary_pattern.html)?
> - The output is (N, M) array and when I look at it is not clear to me what is the output and how do you generate a histogram from it, can someone you please clarify it.
> 
> I know that these questions are be basic and while I was trying to look for answers I found the information more mathematical and less with applied approach. Therefore, any help, ideas or tips will help.
> 
> Thanks for the patience,
> G.
> 
> Hi,
> 
> LBP can be quite confusing at first, but the idea is pretty simple. I recently added some more explanations to the example in the gallery (most of the addition is code to plot things---you don't really need to understand that part of the code):
> 
> https://github.com/scikit-image/scikit-image/blob/master/doc/examples/plot_local_binary_pattern.py
> 
> That example should clarify most of your questions. I don't really know how the boundary is treated, so maybe someone else can clarify that point.
> 
> Best,
> -Tony
> 
> 
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