[SciPy-user] Bug in scipy.integrate.ode?

[LATORNELL, Doug]

In [2]: numpy.__version__
Out[2]: '0.9.7.2247'

In [4]: scipy.__version__
Out[4]: '0.4.7.1711'

Trivial integration of a decaying exponential:

from scipy import *

def f(t, y):
    return -log(2) / 2 * y


r = integrate.ode(f).set_integrator('vode')
r.set_initial_value(1.0)
while r.successful() and r.t <= 2:
    r.integrate(r.t + 0.1)
    print r.t, r.y

Produces:

Python 2.4.1 (#1, Sep  3 2005, 13:08:59) 
Type "copyright", "credits" or "license" for more information.

IPython 0.6.15 -- An enhanced Interactive Python.
?       -> Introduction to IPython's features.
%magic  -> Information about IPython's 'magic' % functions.
help    -> Python's own help system.
object? -> Details about 'object'. ?object also works, ?? prints more.

In [1]: ## working on region in file /tmp/python-23462ATK.py...
Found integrator vode
------------------------------------------------------------------------
---
exceptions.NameError                                 Traceback (most
recent call last)

/home/doug/python/<console> 

/tmp/python-23462ATK.py 
      6 
      7 r = integrate.ode(f).set_integrator('vode')
----> 8 r.set_initial_value(1.0)
      9 while r.successful() and r.t <= 2:
     10     r.integrate(r.t + 0.1)

/usr/local/lib/python2.4/site-packages/scipy/integrate/ode.py in
set_initial_value(self, y, t)
    141     def set_initial_value(self,y,t=0.0):
    142         """Set initial conditions y(t) = y."""
--> 143         if isscalar(y):
    144             y = [y]
    145         n_prev = len(self.y)

NameError: global name 'isscalar' is not defined

The fix appears to be to add 'isscalar' to the 'from numpy import ...'
at line 94 in scipy/integrate/ode.py

Doug



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