[SciPy-user] Transforming 1-d array to 2-d array
Rich Shepard
rshepard at appl-ecosys.com
Mon Feb 26 15:43:37 EST 2007
On Mon, 26 Feb 2007, Dave wrote:
> eye simply creates an array with ones on the diagonal. To solve this
> problem I would create a zero array of the correct size and then index
> into the array.
Hi, Dave,
What, then, is the difference between eye() and identity()?
> #Define array size
> N = 8
>
> #Define the data to put in the upper-diagonal part of the array
> myData = rand(N*(N-1)/2)
Well, rather than random, these data are the averages of averages of each
item in the list of tuples retrieved from the database table.
> #Create an index to the upper-diagonal part
> idx = triu(ones([8,8])-eye(8)).nonzero()
> #Instantiate a zero array and populate the upper-triangular part with myData
> A = zeros([N,N],dtype=float)
> A[idx] = myData
>
> #Place ones on the diagonal
> A += eye(N)
I don't immediately understand what this is doing. I'll have to play with
it in ipython.
Ultimately, I need the averaged item values in the upper half of an 8x8
matrix, 1s along the diagonal, and 1/values in the lower half of the matrix.
Probably not the simplest introduction to NymPy and SciPy, but it's what I
need to do.
Many thanks,
Rich
--
Richard B. Shepard, Ph.D. | The Environmental Permitting
Applied Ecosystem Services, Inc. | Accelerator(TM)
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