[SciPy-user] In-place matrix reordering
Antonino Ingargiola
tritemio at gmail.com
Wed Feb 25 03:12:37 EST 2009
Hi to the list,
I have to "reorder" the columns of a big 2D array (a matrix) but
without doing a temp copy of the whole matrix (since it is 1.5GB).
Basically I would need something like this:
a = arange(12).reshape(4,3)
b = a[:,(2,0,1)]
but without the array copy triggered by the advanced indexing. Let the
(2,0,1) tuple be an arbitrary sequence previously computed.
The .take method seems to do a copy too:
b = a.take((2,0,1), axis=1)
What I need is a "view" of "a" with an arbitrary column order.
Is there a way to accomplish this task?
Ciao,
~ Antonio
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