[SciPy-User] results of scipy.spatial.ConvexHull

[Rafael Silva]

Hi!

Using the code

> import scipy.spatial.qhull as qhull
> import scipy.spatial.qhull as qhull

verts = [
>     [-0.5, -0.5, -0.5],
>     [-0.5, -0.5, 0.5],
>     [-0.5, 0.5, -0.5],
>     [-0.5, 0.5, 0.5],
>     [0.5, -0.5, -0.5],
>     [0.5, -0.5, 0.5],
>     [0.5, 0.5, -0.5],
>     [0.5, 0.5, 0.5],
> ]
> qh = qhull.ConvexHull(verts)
> print(qh.simplices)


I obtained the results:

> [[6 2 0]
> [6 4 0]
> [5 4 0]
> [5 1 0]
> [5 6 4]
> [5 6 7]
> [3 2 0]
> [3 1 0]
> [3 6 2]
> [3 6 7]
> [3 5 1]
> [3 5 7]]


I tried some options using the keyword "qull_options", but I could only get
results consisting of 12 simplices.

Instead, using Qhull library directly

rbox c D3 | qconvex p i


I got the result I wanted with just 6 simplices:

4 6 2 0
> 1 5 4 0
> 5 7 6 4
> 3 1 0 2
> 7 3 2 6
> 3 7 5 1


And using the option "Qt" I got the same result from scipy:

6 2 0
> 4 6 0
> 5 4 0
> 1 5 0
> 5 6 4
> 6 5 7
> 2 3 0
> 3 1 0
> 6 3 2
> 3 6 7
> 3 5 1
> 5 3 7


My question is: I want to get the "merged" version of the convex hull
results for 3-D points. In the example, I want the 6 simplices case instead
of the 12 (N x 3) format.

How could I get that from scipy? Is it possible?

Thank you for help!
Regards,
Rafael.
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