[Tutor] creating files and writing to them
Ivan Van Laningham
ivanlan@callware.com
Thu, 03 Jun 1999 07:57:54 -0600
Hi Todd etc.--
Todd Martin wrote:
>
> Ok so I can do these things in perl and shell but I'm just now learning
> python and am a little confused.
>
> What I want to do is pass a username to a script as an argument like so:
>
> % script username
>
> Then write a file named "username.startup".
>
> This is where I'm at right now:
>
> #! /usr/bin/python
>
> file = open('/home/todd/docname', 'w')
> file.write('The create script in its infancy\n')
> file.close()
>
> def docname ():
> username = "todd"
> startup = ".startup"
> doc = username + startup
> print "%s" % doc
>
> docname()
>
> I know its lame so far but I'm new :)
>
> Ok so that last tidbit there is how I figured I could take the username and
> append ".startup" to it. But now I need to create a file by that name, rather
> than the way its being done now, where I have to declare the file name in
> advance (does that make sense?).
>
> Now I know I will need to pass the username argument to argv, but that can wait untill I find out how to pass file = open() a variable rather than a file name.
>
> Is this clear? I'm not entirely sure I know how to word this right.
>
> Any help would be very appreciated!
>
#!/usr/bin/python
# I see that you're on RedHat Linux;-)
if len ( sys.argv ) > 1 :
homedir = "/home/"
username = sys.argv[1]
startup = "/.startup"
startupfile = open ( homedir + username + startup, 'w' )
file.write('The create script in its infancy\n')
file.close()
else :
print "Usage: %s username" % ( sys.argv[0] )
<ask-us-something-hard>-ly y'rs,
Ivan
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Ivan Van Laningham
Callware Technologies, Inc.
ivanlan@callware.com
http://www.pauahtun.org
See also:
http://www.foretec.com/python/workshops/1998-11/proceedings.html
Army Signal Corps: Cu Chi, Class of '70
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