On Fri, 16 Feb 2001, Lindsay Davies wrote:
> s = re.sub("(\.\s*|^\s*)(\w)", (lambda x: x.group(1) +\
As a safety tip: it's safer to make the regular expression an explicit
"raw" string, because it's only coincidence that '\s' doesn't match up as
a special character:
s = re.sub(r"(\.\s*| ...