[Tutor] String.find won't - why?
Mon, 29 Oct 2001 00:04:17 +0100
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Thanks for all the comments on the readline(s) issue. I have understood =
But please bear with me. Unfortunally the next step in this little =
program is as problematic for me.
Am trying to remove all 0D 0A (Hex). Thought this was done through the =
following while loop.
The file is attached.
The first round things works nicely. The 0D 0A (Hex) is found and =
removed. Pos is correctly 142.
The second round things behave more strangely. Pos will get a wrong =
value (178) but there just is no 0D 0A (Hex) there and so the i:pos =
string will get to short.
Running w2k. Why on earth is this behaving wrongly?
t =3D open('d:/Experiment.txt', 'r')
text =3D t.read() # Read text
a =3D ''
while i < len(text):
pos =3D string.find(text[i:], '\n')
if pos > 0:
a =3D a + text[i:pos]
i =3D i + pos + 1
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