On 8/12/02 1:22 PM, "SA" <sarmstrong13@mac.com> wrote:
>>
> Here is another bit of a cludgeon:
>
>>>> d={}
>>>> for k in l1:
> ... for v in l2:
> ... d[k]=v
> ...
>>>> print d
> {'woo': 'hoo', 'wacky': 'hoo', 'wicky': 'hoo'}
>
>
>
My bad. I just noticed that the output did not iterate properly over l2.
Sorry.
SA
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