[Tutor] urlparse question
Erik Price
erikprice@mac.com
Mon, 26 Aug 2002 09:17:02 -0400
On Monday, August 26, 2002, at 08:42 AM, Jaco.Smuts@za.didata.com wrote:
> using urlparse I can get
>
> urlValue[0] = 'http'
> urlValue[1] = 'www.google.com'
> urlValue[2] = '/search'
> urlValue[3] = ''
> urlValue[4] =
> 'hl=en&lr=&ie=UTF-8&oe=utf-8&q=south+africa+travel+cape+town'
> urlValue[5] = ''
>
> What I'm looking for is a way (using a library, not regex if possible)
> to
> parse out of urlValue[4]
> hl='en'
> lr=''
> ie='UTF-8&oe=utf-8'
> q='south+africa+travel+cape+town'
>
> Any ideas ?
qsDict = {}
for pair in urlValue[4].split('&'):
pair = pair.split('=')
qsDict[pair[0]] = pair[1]
This doesn't use a library, but it doesn't use regexes either, so it
shouldn't be too slow. Still, there's probably a more elegant solution
using lambdas or list comprehensions, but I'm still waiting to hear back
on another thread so I can figure out how to use them! :)
Erik
PS: are you sure you wanted the "ie" variable to be "UTF-8&oe=utf-8", or
was that a typo? Because my solution won't know that it should do
that....
--
Erik Price
email: erikprice@mac.com
jabber: erikprice@jabber.org