# [Tutor] Help with silly algorhythm

kevin parks kp87@lycos.com
Fri, 15 Feb 2002 01:01:13 +0900

```I have been wanting to ask this one for a while, but it is a bit tricky to articulate so I will try my best.

What I want to do is generate a new list of items based on another list and a some
criteria (list of accepable values, for example). So, i might have:

* list of input values =[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
* a list of acceptable new 'partner values' = [1, 3, 7, 10]

and I want a new list made up of the closest member of a list (modulo the
number of list members: here 12 (0-11) of acceptable values
in 4 different ways [upper, lower, or alternating (starting higher, starting lower)]

All with the further stipulation that values from the input list do not team with values
in the "buddy" list if they are the same, so input 1 would not go with 1 from list 2, but
with 3 (the next value up),  or 10 (next value down).

vague i know, i am trying my best...

so we might get (in mode 1: all closest higher value)

[ [0, 1], [1, 3], [2, 3], [3, 7], [4, 7], [5, 7], [6, 7], [7, 11]....

-or-

[1,   3,  3, 7, 7, 7, 7, 11.....]

mode 2 (all closest value down) might be:

[[0,10], [1, 10], [2, 1], [3, 1], [4, 3], [5,3], [6,3], [7,3], [8, 7]....

mode 3

[ [0, 1], [1, 10], [2, 3], [3, 1].....

etc.

So problem number one for me is how do i figure out which value is
'closest' (up or down), do i have to test it against each value of the list
or is there a smarter way.

I realize that this is very odd and convoluted. If it is too stupid a question
please feel free to snub it.

I know i have asked a lot of this list lately and have recieved some
very helpful responses. I am trying to get as much Python in as possible
before the holiday is over.

-kp--

meanwhile i am pouring over the last few tutor digests...

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```