[Tutor] basic python question

[Alan Trautman]

Ron,

I apologize unfortunately I am forced to use VB all day and a M$ ism crept
into my answer. It should read

x=3

if x%2 == 0:
    print x,"is even"
else:
    print x,"is odd"

The == means is this equal to as opposed to = which means assigned to. Sorry
about the problem.

Alan


-----Original Message-----
From: Ron Nixon [mailto:nixonron@yahoo.com]
Sent: Monday, September 23, 2002 8:21 AM
To: Alan Trautman
Subject: RE: [Tutor] basic python question


Still can't get it to work. I keep getting an error message 
 
Ron 
 Alan Trautman wrote: 
Ron,

Python is totally dependant on indentation for program flow.

To make your program work type

if x%2 = 0:
    print x,"is even"
else:
    print x,"is odd"

The indentations tell Python that these are the steps to perform when the
condition is true (ie.. even) or what to do in all other cases (odd).


-----Original Message-----
From: Ron Nixon [mailto:nixonron@yahoo.com]
Sent: Friday, September 20, 2002 9:17 AM
To: tutor@python.org
Subject: [Tutor] basic python question


I'm playing around with the "How to Think Like A Computer Scientist" book
and trying one of the examples and I keep getting syntax errors even though
I'm typing word for word. 
if X%2==0: 
print x, "Is even" 
else: 
print x, "is odd" 
but I get a syntax error on the "else:" as shown below. Can I not do this
with IDLE? 
SyntaxError: invalid syntax
>>> if x%2==0:
 print x, "is even"
 else:
  
SyntaxError: invalid syntax
>>> 





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