[Tutor] Counting matching elements in sequences
Gregor Lingl
glingl at aon.at
Tue Dec 9 15:13:06 EST 2003
>Perhaps it's best to skip the "clever" lambda and reduce
>tricks completely! This works (I think):
>
>def alleq(seq):
> for item in seq[1:]:
> if item != seq[0]:
> return False
> return True
>
>It also works correctly with 0 or 1 elements in the
>sequence (assuming that we consider an empty list to
>have all elements equal--at least there are no
>differences).
>
>
What do you think about:
>>> def alleq(seq):
... return seq == seq[:1]*len(seq)
...
>>> alleq("")
True
>>> alleq((1,))
True
>>> alleq([1,1])
True
>>> alleq((1,2))
False
>>>
Gregor
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