[Tutor] Re:Help on Tutor

[Danny Yoo]

On Mon, 28 Jul 2003, Scott Widney wrote:

> ## Yep. So I'll have to deal with that.
> ## The easiest way would be to just get rid of the fractional part
> >>> int(time.time())
> 1059404248
> ## And it would be much easier to get the last two digits
> ##  if I was dealing with a string.
> >>> str(int(time.time()))
> '1059404275'
> ## Great! Now I just need the last two characters.
> >>> str(int(time.time()))[-2:]
> '89'


Hi Scott,


An alternative way of doing this, without as much string manipulation, can
be to use the "modulo" (remainder) operator.  Anything divided by 100 will
leave a remainder between 0 and 99.

###
>>> int(time.time()) % 100
16
###


Hope this helps!