[Tutor] String matching in 1.5.2 problem

[Reggie Dugard]

I believe in 1.5.2 you have to import the string module and use the find
function.  Something like
import string
...

      if string.find(Y, List1Head) == -1:
	...

This should also work fine in python 2.

HTH,

On Wed, 2003-05-07 at 08:03, Daniel Nash wrote:
> I have a python 1.5.2 string matching problem.
> 
> I have two lists of email addresses:
> 
> list1 = ["dan@NO-SPAM.company.com","fred@NO-SPAM.company.com"]
> 
> and another list made up from the contents extracted from an email's headers
> To:,Cc: & Bcc:
> 
> list2 =[('', 'support@NO-SPAM.company.com'), ('jim', 
> 'jim@NO-SPAM.company.com'), ('',
> 'fred@NO-SPAM.comapny.com')]
> 
> I am trying to write a peice of code that will run in python 1.5.2 to return 
> true if any element in list1 appears in list2.
> 
> In python2 I had this and it served its purpose:
> 
> for X,Y in list2:
>     for List1Head in List1:
>         if Y.find(List1Head) == -1:
>            # if false then do nothing
>             print "Is NOT Addressed to: ", List1Head
>         else:
>             print "Is Addressed to: ", List1Head
> 
> But I have to make it run on 1.5.2 and I get the following message:
> 
> Traceback (innermost last):
>   File "MAILIN.py", line 55, in ?
>     if Y.find(List1Head) == -1:
> AttributeError: 'string' object has no attribute 'find'
> 
> Can anyone tell me how to alter my code to work/improve on my code to only 
> return true on an exact match of an email address rather than a sub string 
> which allows errors as returning ture for MILE.COM WITHIN SMILE.COM?
> 
> _________________________________________________________________
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> 
> 
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-- 
Reggie