[Tutor] hex output

[tpc at csua.berkeley.edu]

hi Jimmy, for the upper casing you use the upper() function like so:

<paste>
>>> hex(3735928559).upper()
'0XDEADBEEFL'
</paste>

the L means long type.  Now if you require all your decimal to hex
conversions to be in the form 0000 without the 0x or L signifiers you
might write a function which takes any hexstring, removes the 0x and L,
checks the length of the hexstring and does the appropriate thing:

<paste>
>>> def dec2hexconverter(x):
	hexstring = hex(x).replace('0x', '').replace('L', '').upper()
	length = len(hexstring)
	if length == 1:
		hexstring = '000' + hexstring
	elif length == 2:
		hexstring = '00' + hexstring
	elif length == 3:
		hexstring = '0' + hexstring
	elif length == 8:
		hexstring = hexstring[:4] + ' ' + hexstring[-4:]
	return hexstring

>>> dec2hexconverter(3735928559)
'DEAD BEEF'
</paste>

Granted, not the most elegant solution, but that should get you started.

On Thu, 4 Sep 2003, Jimmy verma wrote:

> Hello *,
>
> I am having problem in converting hexadecimal no's according to the format i
> require.
>
> >>>hex(65)
> '0x41'
> >>>hex(65)[2:]
> '41'
>
>
> I want to write it in 4 digits form like this  0041
> and also in upper cases.
>
> Your suggestion are welcomed.
>
> Thanks a lot.
>
> Regards,
>
> J+
>
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