[Tutor] embedding an if
sigurd at 12move.de
Thu Apr 1 19:55:22 EST 2004
On 29 Mar 2004, peter hodgson <- py at humnet.ucla.edu wrote:
> tutorial assignment; what am i doing wrong? thanks
I think that password programm is one of the most often mentioned
programs here :-)
> #Modify the password guessing program to keep track of how many times
> # the user has entered the password wrong. If it is more than 3 times,
> # print "you're screwed, buddy!", or something like that;
> passwd = "foobar" #a dummy passwd
> count = 3
> current_count = 0
> while passwd != "unicorn":
> current_count = current_count + 1
> passwd = raw_input("Passwd: ")
> if current_count < count:
> print "no, stupid! try again;"
> else print "three times, you're out!"
> print "welcome in"
(you include tabs in your e-mails; that may result in wrong indentation
in some e-mail clients or programs if someone tries your code)
Did you try that program? It won't run.
If you want to wite an else clause it's written like that:
if foo == bar:
Even if you program ran it wouldn't run in the way you probably
expected; after printing the message you need a way to break the loop:
the statement is called `break' (surprise).
But then your program will process the code after the loop so a user
would always see the welcome message. If you don't want that you need a
way to stop the whole program; you must import the sys module and
Please do *not* send copies of replies to me.
I read the list
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