[Tutor] convert to dict

[Crabtree, Chad]

I know there is a more spiffy way to do this but I can never remember them
this is how I would do it.

IDLE 1.0.2      
>>> lb = ['TEMP01.DBF : 1024', 'TEMP02.DBF : 1024', 'TEMP03.DBF : 1024',
'TEMP04.DBF : 1024', 'TEMP05.DBF : 1024', 'TEMP06.DBF : 1024']
>>> def makeDict(adict):
	result={}
	for x in adict:
		key,value=x.split(':')
		result[key]=value
	return result

>>> makeDict(lb)
{'TEMP02.DBF ': ' 1024', 'TEMP01.DBF ': ' 1024', 'TEMP06.DBF ': ' 1024',
'TEMP05.DBF ': ' 1024', 'TEMP04.DBF ': ' 1024', 'TEMP03.DBF ': ' 1024'}
>>> 

If you need the values to be integers just int() them.



> -----Original Message-----
> From: Larry Blair [mailto:lbblair at adaptisinc.com]
> Sent: Tuesday, April 27, 2004 11:33 AM
> To: tutor at python.org
> Subject: [Tutor] convert to dict
> 
> 
> I have been doing Python for only about 2 weeks so sorry for 
> the beginners
> question. I have looked in the archives, etc. and suspect I don't know
> enough python vocabulary to ask the correct questions. I am 
> converting some
> Jython programs I inherited and I think there are built-ins to do this
> easier in Python.
> 
> I have a string (below) that I want to convert to a 
> dictionary. I think I
> can do it with a for loop and using split but just don't 
> quite have the
> skills to manipulate the data. I am getting the data from a 
> text properties
> file I read into the program.
> 
> Thanks for any help
> Larry
> 
> 
> lb = ['TEMP01.DBF : 1024', 'TEMP02.DBF : 1024', 'TEMP03.DBF : 1024',
> 'TEMP04.DBF : 1024', 'TEMP05.DBF : 1024', 'TEMP06.DBF : 1024']
> 
> 
> 
> 
> 
> 
> 
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