[Tutor] Rounding to n significant digits?

[Dick Moores]

Dragonfirebane at aol.com wrote at 20:58 7/1/2004:
>Look at the Python Docs . . . there exists round(number[, ndigits]) -> 
>floating point number.

 From the Docs:

================================
round( x[, n])

Return the floating point value x rounded to n digits after the decimal 
point. If n is omitted, it defaults to zero. The result is a floating 
point number. Values are rounded to the closest multiple of 10 to the 
power minus n; if two multiples are equally close, rounding is done away 
from 0 (so. for example, round(0.5) is 1.0 and round(-0.5) is -1.0).
====================================

So that won't do it. "rounded to n digits AFTER the decimal point".

But thanks,

Dick